✓1+sinA / 1-sin A = sec A + tan A
Answers
Answered by
1
Answer:
(1−sinA)
(1+sinA)
×
(1+sinA)
(1+sinA)
=
1−sin
2
A
(1+sinA)
2
=
cos
2
A
(1+sinA)
2
=
cosA
1+sinA
=
cosA
1
+
cosA
sinA
=secA+tanA
Answered by
1
Here's ur answer. Hope you like it
Attachments:
Similar questions