Math, asked by ykanu2010, 1 year ago

(1+sinA/1-sinA)^1/2=sec A+tanA

Answers

Answered by sandy1816

1

Step-by-step explanation:

√(1+sinA/1-sinA)

=√(1+sinA)²/1-sin²A

=√(1+sinA)²/cos²A

=(1+sinA)/cosA

=secA+tanA

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