Math, asked by bablu2511, 11 months ago

√1+sinA×√1-sinA=???​

Answers

Answered by Anonymous
0

L.H.S.=√1+sinA/1-sinA

=√(1+sinA)(1+sinA)/(1-sinA)(1+sinA)

=√(1+sinA)^/1-sin^A

=√(1+sinA)^/cos^A

=1+sinA/cosA

= 1/cosA+ sinA/cosA

=secA+tanA

=R.H.S. prove

Answered by shiningsubham
0

Step-by-step explanation:

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