Question

√1+sinA √1-sinA=.............

Answer 1

Answer:

hey mate

Step-by-step explanation:

here is your answer

solution

$\sqrt{ \frac{1 + \sin \: a \: }{1 - \sin \: a } }$

$\sqrt{ \frac{1 + \sin \: a \: }{1 - \sin \: a } } \times \frac{1 + \sin \: a }{1 + \sin \: a }$

$\sqrt{ \frac{ {(1 + \sin \: a \: ) }^{2} }{ {1}^{2} - { \sin}^{2} a} }$

$\sqrt{ \frac{ {(1 + \sin \: a) }^{2} }{ {1 - { \sin }^{2} a} } }$

$\sqrt{ \frac{ {(1 + \sin \: a)}^{2} }{ { \cos }^{2} a } }$

$\frac{1 + \sin \: a}{ \cos \: a }$

$\frac{1}{ \cos \: a } + \frac{ \sin \: a }{ \cos \: a }$

$\sec \: a \: + \tan \: a$

$thanku$