1+sinA/1-sinA=?
please answer
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Answer:
cos^2A+2sinA/cos^2A
And also 1/1+2sinA/cos^2A (if more simplified)
Step-by-step explanation:
1+sinA/1-sinA
=1+sinA/1-sinA×1+sinA/1+sinA
=(1+sinA)^2/(1-sinA)(1+sinA)
=1^2+sinA^2+2sinA/1^2-2sinA
=cos^2A+2sinA/cos^2A
(if more simplified)
=dividing with cos^2A
1+2sinA/cos^2A
or written as 1/1+2sinA/cos^2A
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