Math, asked by schoolw886, 14 days ago

1+sinA/1-sinA=?

please answer

Answers

Answered by Lokesh1429

0

Answer:

cos^2A+2sinA/cos^2A

And also 1/1+2sinA/cos^2A (if more simplified)

Step-by-step explanation:

1+sinA/1-sinA

=1+sinA/1-sinA×1+sinA/1+sinA

=(1+sinA)^2/(1-sinA)(1+sinA)

=1^2+sinA^2+2sinA/1^2-2sinA

=cos^2A+2sinA/cos^2A

(if more simplified)

=dividing with cos^2A

1+2sinA/cos^2A

or written as 1/1+2sinA/cos^2A

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