✓1+sinA/1-sinA prove that secA + TanA
Answers
Answered by
3
Hope it helps you....
Attachments:
Answered by
2
ANSWER--
Taking LHS
=√1-sin A / 1+sin A
Rationalising
= √(1-sin A) / (1+sin A ) x √(1-sin A) / (1-sin A )
= √(1-sin A)2 / (1-sin2 A ) = √(1-sin A)2 / cos2 A
= (1-sin A) / cos A = (1/cos A - sin A/cos A)
= sec A - tan A. √1-sin A / 1+sin A
= sec A - tan A. Hence proved
Taking LHS
=√1-sin A / 1+sin A
Rationalising
= √(1-sin A) / (1+sin A ) x √(1-sin A) / (1-sin A )
= √(1-sin A)2 / (1-sin2 A ) = √(1-sin A)2 / cos2 A
= (1-sin A) / cos A = (1/cos A - sin A/cos A)
= sec A - tan A. √1-sin A / 1+sin A
= sec A - tan A. Hence proved
Similar questions