Question

1+sinA ÷1-sinA=(sec+tan) wholesquare

Answer 1

Hey there !

1+sin A / 1- SinA = (secA + tan A) ²

L.H.S = 1+sinA/1-sinA

R.H.S = (secA + tan A) ²


multiply ✖ L.H.S by 1+SinA / 1+SinA


L.H.S= 1+sinA/1-sinA

=(1+sinA)²/1-sin²A

=(1+sinA)²/cos²A

= [ 1+sinA / cosA ] ²

=[ 1/cosA + sinA / cosA ] ²

=[ secA +tanA ] ²

=R.H.S

Formulae used here : -

(a+b)(a+b)=(a+b)²

(a+b)(a-b)=a²-b²

1/cosA = secA

sinA / cosA = tanA

a²/b²=(a/b)²

hope helped !