Question

√1-sinA/1+sinA=secA -tanA​

Answer 1

Step-by-step explanation:

√1-sinA/1+sinA=secA -tanA

L.H.S =√1-sinA/1+sinA

√1-sinA/1+sinA × 1- sinA/ 1- sinA

√1-sin^2A/1+ sin^2

√cos^2 A/1+sin^2A

cos A / 1+sin A

cos A / 1 + cos A / sin A

using Invertendo

1/cos A - sin A / cos A

sec A - tanA

Answer 2

Here's your answer dear (◔‿◔)(◔‿◔)

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