Math, asked by vittalbadagandi793, 1 year ago

√1+sinA/√1-sinA=secA+tanA

Answers

Answered by sandy1816

1

Step-by-step explanation:

√1+sinA/1-sinA

=√(1+sinA)²/1-sin²A

=√(1+sinA)²/cos²A

=1+sinA/cosA

=secA+tanA

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