Question

√1+sinA/1-sinA=secA+tanA​

Answer 1

Answer:

please have a look at the answer

Step-by-step explanation:

Step-by-step explanation:please mark it as the brainliest

Answer 2

Answer:

LHS

= √ 1+sin A / 1- sin A

= √(1+sinA)(1-sinA) / √ (1-sinA)^2

= √1-sin^2 A / 1-sin A

= cos A / 1- sin A

= cos A(1+sin A)/1-sin^2 A

= (1+sinA)cos A/cos^2 A

= (1+sinA)/cos A

= sec A + tan A

= RHS

Hope this helps you !