Question

√1-sinA/1+sinA=secA-tanA

Answer 1

Answer:

Step-by-step explanation:

multiply and divide with √1-sinA   we get

√(1-sinA)(1-sinA)/(1+sinA)(1-sinA)

in the numerator the root gets cancelled leaving this

(1-sinA)/√1-sin²A                         (a+b)(a-b)=a²-b²

as we know sin²A+cos²A=1      1-sin²A will be cos²A

so in the denominator we get

(1-sinA)/√cos²A  which gives us

(1-sinA)/cosA

splitting cosA for each term we get

1/cosA-sinA/cosA    which is equal to

secA-tanA

I REALLY HOPE THIS HELPS YOU