Question

1-sinA/1+sinA=(secA-tanA)^2
​

Answer 1

Answer:

LHS = 1-sin A/1+sin A = (1-sinA)^2/1-sin^2 A

= (1-sin A)^2/cos^2 A

= (1-sin A/cos A )^2

= (secA-tanA)^2

= RHS

Hope this helps you !

Answer 2

Hope it helps dear mate!! please mark as BRAINLIEST!!