Math, asked by tanushkagauvas, 7 months ago

1-sinA/1+sinA=(secA-TanA)²​

Answers

Answered by TheGalacticWarrior
1

Answer:

Step-by-step explanation:

\frac{1-\sinA}{1+\sinA}

=\frac{(1-\sinA)^2}{1-\sin^2A}

\left \frac{1-\sinA}{\cosA} \right^2

=(\secA-\tanA)^2

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