Question

1-sinA/1+sinA
=secA -tanA​

Answer 1

/* There is a mistake in the question. It must be like this */

$\red{ \sqrt{ \frac{(1-sin A)}{ (1 + Sin A }} = Sec A - tan A }$

$LHS = \sqrt{ \frac{(1-sin A}{ (1 + Sin A )}}$

$= \sqrt{ \frac{(1-sin A)(1-sin A )}{ (1 + Sin A)(1 - Sin A ) }}$

$= \sqrt{\frac{ ( 1 - sin A )^{2}}{ 1^{2} - sin^{2} A } }$

$= \sqrt{\frac{ ( 1 - sin A )^{2}}{ 1 - sin^{2} A } }$

$= \sqrt{\frac{ ( 1 - sin A )^{2}}{ cos^{2} A } }$

$= \frac{1 - sin A }{ cos A } \\= \frac{ 1}{cos A } - \frac{Sin A}{Cos A }$

$= Sec A - tan A \\= RHS$

$Hence \:proved .$

•••♪

Answer 2

Answer:

Heya mate here's the answer Mark as brainliest pleaseeeeee ‼️