Math, asked by krishnaik91, 3 months ago

√1+sinA/1-sinA=secA+tanA

Answers

Answered by akshaybarhate117

0

Step-by-step explanation:

LHS=

1−sinA

1+sinA

=

1−sinA

1+sinA

×

1+sinA

1+sinA

=

(1+sinA)(1−sinA)

(1+sinA)

2

=

1−sin

2

A

(1+sinA)

2

=

cos

2

A

(1+sinA)

2

=

(

cosA

1+sinA

)

2

=

cosA

1+sinA

=

cosA

1

+

cosA

sinA

=secA+tanA

=RHS

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