Question

1+sinA/1-sinA=tan^2 * (45+A/2)

Answer 1

Answer:

Giving Answer -

tan^2(pi/4+A/2)

= [(1+tanA/2)/(1-tanA/2)]^2

= [(cosA/2 + sinA/2)/(cosA/2 - sinA/2)]^2

= [(cos^2(A/2) - sin^2(A/2))/(1 - sinA)]^2

= [cosA/(1-sinA)]^2

= (1-sin^2(A))/(1-sinA)^2

= (1+sinA)/(1-sinA)

Thank You

$we \: value \: your \: care$

Answer 2

Thanks for free points

sorry don't know the answer