Math, asked by ankitkuma76543, 11 months ago

√1+sinA/1-sinA=tanA+secA

Answers

Answered by Anonymous

1

Step-by-step explanation:

√(1+SinA/1-SinA) × (1+SinA/1+SinA)

√(1+SinA)²/(1-Sin²A)

√(1+SinA)²/Cos²A

(1+SinA)/CosA

1/CosA + SinA/CosA

SecA + tanA

Answered by has42000

0

Answer:

Trigonometry

Step-by-step explanation:

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