Question

√(1+sinA/1-sinaA)=secA+tanA​

Answer 1

Answer:

LHS=RHS

Step-by-step explanation:

LHS =√1+sinA ×1+sinA÷√1-sinA×1+sinA

LHS= √(1+sinA)^2÷√1-sin^2A

LHS= √(1+sinA)^2 ÷√cos^2A

LHS= 1+sinA ÷ cosA

LHS= 1/cosA + sinA/cosA

LHS= secA + tanA

LHS=RHS