Question

1+sinA.1+sinB.1+sinC=1-sinA.1-sinB.1-sinC=k then k=

Answer 1

Answer:

k= 2

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Answer 2

Answer:

y = - cos A cos B cos C

Step-by-step explanation:

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Asked on December 30, 2019 by

Lavadiya Prasad

Let x=(1+sinA)(1+sinB)(1+sinC),y=(1−sinA)(1−sinB)(1−sinC) and If x=y then

THIS QUESTION HAS MULTIPLE CORRECT OPTIONS

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ANSWER

Given :

x=(1+sinA)(1+sinB)(1+sinC) ....... (i) and

y=(1−sinA)(1−sinB)(1−sinC) ....... (ii)

On multiplying both the equation we get

xy=(1−sin

2

A)(1−sin

2

B)(1−sin

2

C)

∴xy=cos

2

Acos

2

Bcos

2

C

If x=y, then

x

2

=cos

2

Acos

2

Bcos

2

C

⟹x=±cosAcosBcosC

⟹y=±cosAcosBcosC

Hence, option A and C are correct.