Question

(1+sinA)^2+(1-cosA)^2=3+2(sinA-cosA)

Answer 1

Solution :-

Q : (1 + sinA)² + (1 - cosA)² = 3 + 2(sinA - cosA)

Considering L.H.S :

(1 + sinA)² + (1 - cosA)²

= 1 + sin²A + 2sinA + 1 + cos²A - 2cosA

= 2 + sin²A + 2sinA + (1 - Sin²A) - 2cosA

= 2 + sin²A + 2sinA + 1 - sin²A - 2cosA

= 3 + 2(sinA - cosA) = R.H.S

Hence, proved

Answer 2

Answer:-

Refer the attachment