(1-sinA
+cos A) square =2(1-sin A) (1 +cos A)
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Answer:
Step-by-step explanation:
(1 - SinA+CoSA)²
= (1 - SinA)² + Cos²A + 2(1 - SInA)(CosA)
= 1 + Sin²A - 2SinA + Cos²A + 2CosA - 2SinACosA
= 1 + (Sin²A + Cos²A) - 2SinA + 2CosA - 2SinACosA
= 1 + 1 - 2SinA + 2CosA - 2SinACosA
= 2 - 2SinA + 2CosA - 2SinACosA
= 2[1 - SinA + CosA - SinACosA]
= 2[ (1 - SinA) + CosA(1 - SinA)]
= 2[(1 - SinA)(1 + CosA)]
= R.H.S
Hence proved.
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