Question

1+sina-cosa /1+Sina+cosa

Answer 1

Step-by-step explanation:

1+sinA-cosA/1+sinA+cosA

devide SinA in both numerator & denominator

=cosecA+1-cotA/cosecA+1+cotA

={(cosecA-cotA)+1}(cosecA+cotA)/ (cosecA+cotA+1)(cosecA+cotA)

=cosec²A-cot²A+cosecA+cotA/ (cosecA+cotA+1)(cosecA+cotA)

=1+cosecA+cotA/ (cosecA+cotA+1)

(cosecA+cotA)

=cosecA+cotA

=1/sinA+cosA/sinA

=1+cosA/sinA