Question

(1+sinA-cosA/1+sinA+cosA)²=1-cosA/1+cosA
Guys plz answer it
And I don't want any rubbish answer otherwise I will report it​

Answer 1

(1-cosA+sinA)/(1+cosA+sinA)}^2= (1-cosA)/(1+cosA)

L.H.S.

={(1-cosA)+sinA}^2/{(1+cosA)+sinA}^2.

={(1-cosA)^2+sin^2A+2.(1-cosA).sinA}/{(1+cosA)^2+sin^2A+2.(1+cosA).sinA}.

={1–2.cosA+cos^2A+sin^2A+2.(1-cosA).sinA}/{1+2.cosA+cos^2A+sin^2A+2.

(1+cosA).sinA}.

={2(1-cosA)+2.(1-cosA).sinA}/{2(1+cosA)+2.(1+cosA).sinA}

= 2.(1-cosA).(1+sinA)/2.(1+cosA).(1+sinA).

= (1-cosA)/(1+cosA). Proved.