Question

(1+sinA-cosA/1+sinA+cosA)²=(cosecA+cotA)²​

Answer 1

Answer:

L.H.S.=(cosecA-cotA)²

=(1/sinA-cosA/sinA)². [:.sinA=1/cosecA]

=(1-cosA/sinA)²

=(1-cosA)²/Sin²A

=(1-cosA)(1-cosA)/1-cos²A

=(1-cosA)(1-cosA)/(1+ CosA)(1-cosA)

=1-cosA/1+ CosA

=R.H.S.

Step-by-step explanation:

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