1 + SinA/cosA=1+sinA+cosA/cosA+1-sinA
Answers
Answered by
2
(sinA + 1 - cosA) / (cosA - 1 + sinA)
Divide each term by cosA
(tanA + secA - 1) / (1 - secA + tanA)
=[tanA + secA - ( sec2A−tan2A )] /
( 1 - secA + tanA)
= (tanA+secA)( 1 - secA + tanA )/(1 - secA + tanA)
= tanA + secA
= (sinA / cosA )+ 1 / cosA
= (sinA + 1 )/ cosA
Hence Proved
Similar questions