Math, asked by sweetpriya1805, 10 months ago

1+sina -cosa /1+sina+cosa=root1-cosa/1+cosa

Answers

Answered by legend2152
1

here is the solution

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Answered by sandy1816
0

LHS

 \frac{1 + sina - cosa}{1 + sina + cosa}  \\  \\  =  \frac{ \frac{1 + sina - cosa}{sina} }{ \frac{1 + sina + cosa}{sina} }  \\  \\  =  \frac{coseca - cota + 1}{coseca + cota + 1}  \\  \\  =  \frac{(coseca - cota) + ( {cosec}^{2}a -  {cot}^{2}  a)}{coseca + cota + 1}  \\  \\  =  \frac{(coseca - cota)(1 + coseca + cota)}{(1 + coseca + cota)}  \\  \\  = coseca - cota

RHS

 \sqrt{ \frac{1 - cosa}{1 + cosa} }  \\  \\  =  \sqrt{ \frac{1 - cosa}{1 + cosa} \times  \frac{1 - cosa}{1 - cosa}  }  \\  \\  =  \sqrt{ \frac{( {1 - cosa})^{2} }{1 -  {cos}^{2} a} }  \\  \\  =  \sqrt{ \frac{( {1 - cosa})^{2} }{ {sin}^{2} a} }  \\  \\  =  \frac{1 - cosa}{sina}  \\  \\  = coseca - cota

 \therefore \:  LHS = RHS

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