Question

1+sina +cosa/1-sina cosa =seca+tana

Answer 1

Step-by-step explanation:

(sinA + 1 - cosA) / (cosA - 1 + sinA)

Divide each term by cosA

=(tanA + secA - 1) / (1 - secA + tanA)

=[tanA + secA - ( sec2A−tan2A)] /

( 1 - secA + tanA)

= (tanA+secA)( 1 - secA + tanA )/(1 - secA + tanA)

= tanA + secA

= (sinA / cosA )+ 1 / cosA

= (sinA + 1 )/ cosA

=1/sinA+sinA/cosA

=secA+tanA

Hence Proved

Hope it will help you

Answer 2

Answer:

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