Math, asked by konain97, 11 months ago

(1+sinA-cosA )/(1+sinA-cosA) square = 1_cosA/1+cosA ​

Answers

Answered by Anonymous
4

Step-by-step explanation:

Left Hand Side = (1 + sinA - cosA ) ÷ (1 + sinA + cosA)²

= (1 + sin²A + cos²A + 2sinA - 2sinAcosA - 2cosA) ÷ (1 + sin²A + cos²A + 2sinA + 2sinAcosA + 2cosA)²

=(1 + 1 + 2sinA - 2sinAcosA - 2cosA) ÷ (1 + 1 + 2sinA + 2sinAcosA + 2cosA)²

= 2(1 +sinA) - 2cosA (sinA + 1 ) ÷ 2(1 + sinA) + 2cosA(sinA +1 )²

= 2(1 + sinA) [1 - cosA] ÷ 2(1 + sinA )(1 + cosA )²

= ( 1 - cosA ) ÷ ( 1 + cosA )²

= Right Hand Side


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