1+sinA/cosA=√2+1 find 1-sinA/cosA=? with explanation
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smruti2002:
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√2+1=1+sinA/cosA
=>1/√2+1=cosA/1+sinA
=cosA(1-sinA)/(1+sinA)(1-sinA)
=cosA-sinA*cosA/1-sin^2 A
=cosA(1-sinA)/cos^2 A
=1-sinA/cosA
so 1-sinA/cosA=1/√2+1=√2-1
=>1/√2+1=cosA/1+sinA
=cosA(1-sinA)/(1+sinA)(1-sinA)
=cosA-sinA*cosA/1-sin^2 A
=cosA(1-sinA)/cos^2 A
=1-sinA/cosA
so 1-sinA/cosA=1/√2+1=√2-1
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