Question

(1-sinA-cosA)^2 = 2(1-sinA) ( 1-cosA)
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Answer 1

Answer:

(1-sinA-cosA)²=2(1-sinA) ( 1-cosA)

LHS

(1-sinA-cosA)²

(1)²+(-sinA)²+(-cosA)²+2(1)(-sinA)+2(-sinA)(-cosA)+2(1)(-cosA)

1+sin²A+cos²A -2sinA+2sinAcosA-2cosA

1+1 -2sinA+2cosAsinA-2cosA

2-2sinA+2cosAsinA-2cosA

2(1-sinA+sinAcosA-cosA)

RHS

2(1-sinA) ( 1-cosA)

2(1(1-cosA)-sinA(1-cosA))

2(1-cosA-sinA+sinAcosA)

therefore, LHS=RHS

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