(1+sinA)/cosA+cosA/(1+sin)
Answers
Answered by
0
What you want rhs is not given or some statement is missing
Answered by
3
cosA/(1 + sinA) + (1 + sinA)/cosA
= {cos²A + (1 + sinA)²} / cosA(1 + sinA)
= {cos²A + 1 + sin²A + 2sinA} / cosA(1 + sinA)
Use sin²∅ +cos²∅ =1
= (1 + 1 + 2sinA) / cosA(1 + sinA)
= 2(1 + sinA) / cosA( 1 + sinA)
= 2 / cosA
= 2secA
cosA/(1 + sinA) + (1 + sinA)/cosA = 2secA
Similar questions