1+sinA/cosA+cosA/1+sinA=2secA=2√1+tan^2A
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(1+sinA)/COSA +cosA/(1+sinA)
=[(1+sinA)^2+COS^2A]/COS A(1+sinA)
=(1+2SinA+sin^2A+cos^2A)/cosA(1+sinA)
=(1+2SinA+1)/COS A(1+sinA)
=(2+2sinA)/COS A(1+sinA)
=2(1+sinA)/cosA(1+sinA)
=2/cosA
=2secA
=2√1+tan^2A
RHS.
=[(1+sinA)^2+COS^2A]/COS A(1+sinA)
=(1+2SinA+sin^2A+cos^2A)/cosA(1+sinA)
=(1+2SinA+1)/COS A(1+sinA)
=(2+2sinA)/COS A(1+sinA)
=2(1+sinA)/cosA(1+sinA)
=2/cosA
=2secA
=2√1+tan^2A
RHS.
yashakhare46p32f3n:
can you please explain last two lines from 2secA
i took common 2 then it will remain 1+sinA. in denominator also 1+sinA. cancelled 1+sinA.
1/cosA =secA
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