Question

1/(sinA+cosA)+(sinA-cosA)=2sinA/1-2cos2A



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Answer 1

Answer:

Hey friend (^_^)

Here is correct question and answer

1/(sinA+cosA)+(1/sinA-cosA)=2sinA/1-2cos2A

LHS :

=(1/sinA+cosA)+(1/sinA-cosA)

TAKING LCM

=(sinA-cosA+sinA+cosA)/(sin²A-cos²A)

[Using sin²A=1-cos²A]

=2sinA/(1-cos²A-cos²A)

=2sinA/(1-2cos²A)

=RHS

HENCE PROVED

HOPE THIS HELPS YOU