(1+sina)square-1 by (1+sina)square +1
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(1+sin a)²-1 ÷ (1+sin a)² +1
= Taking (1+sin a)² -1 as conjugate
we get,
={ (1+ sin a)⁴+1-2[1(1+sin a)²] } ÷ { ((1 +sin a)²)² - 1² }
Here is your answer buddy...
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