Math, asked by parineetasakshi5337, 11 months ago

1-sinAcosA =(sin^3 A+cos^3 A)/(cosA+sinA)

Answers

Answered by sandy1816

0

Step-by-step explanation:

(sin³A+cos³A)/(sinA+cosA)

=(sinA+cosA)(sin²A-sinAcosA+cos²A)/(sinA+cosA)

=(1-sinAcosA)

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