Question

1-sine
1-sin o .....(1)
coso
R.H.S = sec 0 - tan O
1-sino
..... (2)
cos
.. from (1) and (2), L.H.S = R.H.S​

Answer 1

Answer:

hey user

Step-by-step explanation:

» sec A (1-sinA) (sec A+tanA)

»secA -secA. sinA (secA+tanA)

»secA-1/cosA.sinA(secA+tanA)

»(secA-tanA) (secA+tanA)

\sec(a)  {}^{2}  -   \tan(a)  {}^{2}  = 1

Answer 2

Answer:

Question Kaha hai

Ye to solution hai