Math, asked by chinmoychetia21, 10 months ago

√1+sino/ 1-sino
+
√1-sino / 1+sin 0
= 2 sec​

Answers

Answered by zoya12515
14

Answer:

√1+sino/1-sino+√1-sino/1+sino=2seco

Step-by-step explanation:

=[(√1+sino)(√1+sino)/(√1-sino)(√1+sino)]+[(√1-sino)(√1-sino)/(√1+sino)(√1-sino)]

=[(√1+sino)^2/(1-sino^2)+[(√1-sino)^2/(1-sino^2)

=[(√1+sino)^2+(√1-sino)^2/coso^2

=[(1+sino)+(1-sino)/(coso)]

=[(2)/(coso)

=2seco

Hence proved!

Answered by garimaa410
1

Answer:

solution is in the image....

Step-by-step explanation:

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