√1+sino/ 1-sino
+
√1-sino / 1+sin 0
= 2 sec
Answers
Answered by
14
Answer:
√1+sino/1-sino+√1-sino/1+sino=2seco
Step-by-step explanation:
=[(√1+sino)(√1+sino)/(√1-sino)(√1+sino)]+[(√1-sino)(√1-sino)/(√1+sino)(√1-sino)]
=[(√1+sino)^2/(1-sino^2)+[(√1-sino)^2/(1-sino^2)
=[(√1+sino)^2+(√1-sino)^2/coso^2
=[(1+sino)+(1-sino)/(coso)]
=[(2)/(coso)
=2seco
Hence proved!
Answered by
1
Answer:
solution is in the image....
Step-by-step explanation:
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