Question

(1-sinø+cosø)²=(1+cosø)(1-sinø)​

Answer 1

Consider the LHS:

${(1-sinA+cosA)^2 }$

= ${[(1-sinA) + cosA]^2 }$

= ${ (1-sinA)^2 + cos^2A + 2(1-sinA)cosA }$

= ${1 + sin^2A − 2sinA + cos^2A + 2(1-sinA)cosA }$

= ${ 1 + (sin^2A + cos^2A) − 2sinA + 2(1-sinA)cosA }$

= ${1 + 1 − 2sinA + 2(1-sinA)cosA }$

${[Since, sin^2A + cos^2A =1] }$

= ${ 2 − 2sinA + 2(1-sinA)cosA }$

= 2(1 − sinA) + 2(1-sinA)cosA

= 2(1 − sinA)(1 + cosA) = RHS

$\huge\red{brainliest\:plz}$ ❤️

Answer 2

Step-by-step explanation:

Hope this will help you mate