Question

(1-sinQ) (1+sinQ) (1+tan²Q)​

Answer 1

Answer:

(1+tan²Q)(1-sin²Q)

We know that (1+tan²Q)=sec²Q=1/cos²Q

And also 1-sin²Q=cos²Q

So,

1/cos²Q × cos²Q =1

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Answer 2

I don't know how to solve this