(1+SinQ +CosQ) (1-CosQ+SinQ)=?
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Answer:
Let 1+sinQ=a and cosQ=b
(1+SinQ +CosQ) (1-CosQ+SinQ)
=(1+SinQ +CosQ) (1+SinQ-CosQ)
=(a+b)(a-b)
=a^2-b^2
=(1+SinQ)^2-(CosQ)^2
=1+2SinQ+Sin^2Q-Cos^2Q
=Sin^2Q+Cos^2Q+2SinQ+Sin^2Q-Cos^2Q
=2Sin^2Q+2SinQ
=2SinQ(SinQ+1) [Ans]
Using formula:-a^2-b^2=(a+b)(a-b)
Sin^2Q+Cos^2Q=1
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