Question

(1+sintheta)square+(1-sin theta)square/cos square theta= 2{1+sin square theta/1-sin square theta}​
plz answer

Answer 1

Answer:

${(1 + \sin) }^{2} + {( 1 - \sin)}^{2} \div { \cos }^{2} \: \: \: \: lhs \\ 1 + { \sin }^{2} + 2 \sin + 1 + { \sin }^{2} - 2 \sin \div { \cos }^{2} \\ 2 + 2 { \sin }^{2} \div { \cos }^{2} \\ 2(1 + { \sin }^{2} ) \div { \cos }^{2} \\ \\ 2(1 + { \sin }^{2} ) \div (1 - { \sin }^{2} ) \: \: \: rhs \\ 2(1 + { \sin }^{2} ) \div { \cos }^{2} \\ so \\ lhs = rhs \\ hope \: you \: understand \\ and \: follow \: me$