1+ sinx =
1-cosx =
write the formula
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1) 1+ sinx =
1 + sinx = [cos(x/2 ) + sin(x/2)]^2
2) 1-cosx =
we know that cos 2x=cos^2 x-sin^2 x
cos 2x=(1-sin^2 x)-sin^2 x
cos 2x=1–2sin^2 x
by this
1- cos 2x = 2sin^2 x
putting x=x/2;we get ,
1- cos x = 2sin^2 x/2
hope it will help you....
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