Question

√1-sinx/1+sinx=secx - tanx.
find the quadrant of x

Answer 1

Given:

$\sqrt{ \frac{1- \sin x}{1+ \sin x}}= \sec x - \tan x$

To find:

prove the value.

Solution:

The given question is proving type so, its solution can be defined as follows:

$\to \sqrt{ \frac{1- \sin x}{1+ \sin x}}= \sec x - \tan x$

Solve the L.H.S part:

$\to \sqrt{ \frac{1- \sin x}{1+ \sin x} \times \frac{1- \sin x}{1- \sin x} }\\\\\to \sqrt{ \frac{(1- \sin x)^2}{1^2- \sin^2 x} }\\\\ \to \sqrt{ \frac{(1- \sin x)^2}{\cos^2 x} }\\\\\to \frac{(1- \sin x)}{\cos x} \\\\\to \frac{1}{\cos x} - \frac{\sin x}{\cos x} \\\\\to \sec x - \tan x$

So, L.H.S = R.H.S

Answer 2

Step-by-step explanation:

now back to the bish whi had some fookin problem with me, ainr you know boi