Question

1 + sinx
plzzz find the value ... According to inverse trigonometry​

Answer 1

Answer:

There is no precise formula as such. But (1+SinX) can be written in other trigonometric ratios form .

As we know, Sin²X + Cos²X = 1

=> 1- Sin²X = Cos²X

=> (1+SinX) (1- SinX) = Cos²X

=> (1+SinX) = Cos²X / (1-SinX) ………..(1)

OR, 1+ SinX = 1+ (1/CosecX )

=>( 1+SinX) = (CosecX +1)/CosecX ……(2)

OR, (1+SinX) = 1+ √(1-Cos²X) ………(3)

OR, (1+SinX) = 1+(1/√(Cot²X+1) …….(4)