Question

1. Six paving stones are arranged in a square array as shown in the figure. If each stone has a length 20 cm greater than its width, find

(a) the dimensions of each stone,
(b) the area of the ground space that the stones are occupying,
(c) perimeter of the same ground space.​

Answer 1

Step-by-step explanation:

Solution A

As array is in square shape. So, all sides will be equal.

Then,we have

• Length of Array =

$(x + 20) + ( x + 20) = 2 x + 40$

( Length of two paving stones together)

• Width of Array=

$(x + x + x) = 3x$

(Width of three paving stones together)

Now,

Length=Width

$= > 2x + 40 = 3x \\ = > x = 40cm$

Putting values -

Length of array(length of 2 paving stones) =

$2x + 40 =( 2 \times 40) + 40 \\ = > 120cm$

Length of each paving stone=

$120 \div 2 = 60cm$

Width of array(3 paving stones) =

$120cm$

(As it is square, so width=length)

$width \: of \: each \: paving \: stone \\ 120 \div 3 = 40cm$

Solution B

Area of ground space = Area of array

We, know area of square=

${(side)}^{2}$

So, Area=

$120cm \times 120cm = {14400cm}^{2}$

Solution C

Perimeter of ground space=$4 \times side = 4 \times 120cm = 480cm$

HOPE IT WILL HELP YOU.

Answer 2

Answer:

1.40,60cm

2.14400cm square.

3.480cm