Math, asked by jesika09, 5 months ago

1. Solve : 3p² +2 root5p-5=0​

Answers

Answered by nitinjaiswal8948
1

Answer:

Solution Compare 3p2 + 2√5p – 5 = 0 with the Standard form ax2 + bx +c = 0

a = 3, b = 2√5, c = −5 .

p = (−b ± √[b2 − 4ac]) / 2a

substituting the values of a, b and c in the formula we get,

x = √5/3 , - √5

Answered by legend1560
3

your answer is written in two methods in above pictures.

  1. factorisation method
  2. formula method

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