Question

1:Solve:
3x2-2✓6x+2=0​

Answer 1

Answer:

solve by middle term and yourself

Answer 2

Answer:

$x = \frac{\sqrt{6} }{3} , \frac{\sqrt{6} }{3}$

Explanation:

Given quadratic equation  = 3x² -2√6x + 2 = 0

Now, by middle term splitting,

= 3x² -√6x -√6x + 2 = 0

⇒ √3x ( √3x - √2) - √2 ( √3x  -√2) = 0

⇒ (√3x -√2) (√3x -√2) = 0

⇒ √3x - √2 = 0    Or   √3x - √2 = 0

⇒ √3x = √2         Or    √3x = √2

⇒  $x =\frac{\sqrt{2} }{\sqrt{3} }$            Or     $x =\frac{\sqrt{2} }{\sqrt{3} }$

⇒ $x = \frac{\sqrt{2} }{\sqrt{3} } X \frac{\sqrt{3} }{\sqrt{3}}$     Or     $x = \frac{\sqrt{2} }{\sqrt{3} } X \frac{\sqrt{3} }{\sqrt{3}}$  

⇒ $x = \frac{\sqrt{2} X \sqrt{3} }{\sqrt{3} X\sqrt{3} }$      Or    $x = \frac{\sqrt{2} X \sqrt{3} }{\sqrt{3} X\sqrt{3} }$

⇒ $x = \frac{\sqrt{6} }{3 }$            Or    $x = \frac{\sqrt{6} }{3 }$

Hence, $x = \frac{\sqrt{6} }{3} , \frac{\sqrt{6} }{3}$

Hope you got that.

Thank You!