Math, asked by ananthajithnai, 8 months ago

1.Solve:√3y + √2x =0 √2y+√5x=0

Answers

Answered by rockstarman
0

Answer:

y will get answer

Answered by Anonymous
1

Here, the given pair of linear eq. is

 \sqrt{2} x -  \sqrt{3} y = 0...(i)

 \sqrt{5} x  + \sqrt{2} y = 0...(ii)

multiply (1) by \sqrt{2} and (2) by \sqrt{3} to make the coefficient y equal, we get,

2x -  \sqrt{6} y = 0.....(iii) \:  \: ( \therefore  \sqrt{2}  \times  \sqrt{2}  =   ( \cancel{√ }{2)}^{ \cancel{ 2} } = 2)

 \sqrt{15} x  +  \sqrt{6} y = 0.....(iv) \:  \: ( \therefore  \sqrt{5}  \times  \sqrt{3}  =   \sqrt{5 \times 3}  =  \sqrt{15}  \: and \:  \sqrt{2}  \times  \sqrt{3}  =  \sqrt{2 \times 3}  =  \sqrt{6} )

adding eq (iii) and (iv), we get,

(2 +  \sqrt{15} )x = 0

 =  > x = 0

substitute x=0 in eq (ii), we get,

 \sqrt{2} y = 0

 =  > y = 0

hence, the required solution of the given pair of linear eq. is x = 0 and y = 0

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