Question

1) solve
a.4x-5x+2x=28+3x
b.24=y+2y+3+4y
​

Answer 1

$a. \: 4x-5x+2x=28+3x\\ x = 28 + 3x \\ 3x - x = - 28 \\ 2x = - 28\\ x = \frac{-28}{2}\\ x = - 14$

$b. \: 24=y+2y+3+4y \\ 7y = 24 - 3 \\ 7y= 21 \\ y = \frac{21}{7} \\ y = 3$

Answer 2

$\tt \huge {\underline {\underline{ \purple{ Answer : }}}}$

$\fbox{a. ~x ~=~ -14}$

$\fbox{b.~y~=~3}$

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$\tt \huge {\underline {\underline{ \purple{ Solution : }}}}$

$\tt \large\fbox {\purple{a. \: 4x - 5x + 2x = 28 + 3x}} \\ \\ \tt \: \implies \: 4x - 5x + 2x - 3x = 28 \\ \\ \implies \tt \: 6x \: - \: 8x = 28 \\ \\ \implies \tt - 2x = 28\\ \\ \tt \implies \: x = \frac{28}{ - 2} \\ \\ \tt\implies \: x = - 14 \\ \\ \\ \tt \large \underline {\purple{ lets \: \: check \: !}}\\ \\ \\ \tt \large \underline \pink{LHS : }\\ \\ \tt \large 4x - 5x + 2x \\ \\ \tt = 4( - 14) - 5( - 14) + 2( - 14) \\ \\ \tt = - 56 + 70 - 28 \\ \\ \tt = 84 - 70 \\ \\ \tt = - 14 \\ \\ \\ \tt \large \underline \pink{ RHS: } \\ \\ \tt \large28 + 3x \\ \\ = 28 + 3( - 14) \\ \\ \tt = -14 \\ \\ \\ \tt \pink{ LHS = RHS} \\ \\ \tt \purple{\therefore \: the \: \: value \: \: of \: \: x \: \: = - 14} \\ \\ \large\tt \: Hence, \: \: checked!$

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$\tt \ \large \fbox{ \purple{b. \: 24 \: = \: y \: + \: 2y \: + \: 3 \: + \: 4y}} \\ \\ \implies \tt24 - 3 = y + 2y + 4y \\ \\ \tt \implies \: 21 = 7y \\ \\ \tt \implies \: \frac{21}{7} = y \\ \\ \tt \implies3 = y \\ \\ \tt \implies \: y = 3 \\ \\ \\ \tt \large \underline{ lets \: \: check !} \\ \\ \\ \tt \large \underline \pink{LHS \: = \: 24} \\ \\ \\ \tt \large \underline \pink{RHS : } \\ \\ \tt \large y \: + \: 2y \: + \: 3 \: + \: 4y \\ \\ \tt = 3 + 2(3) + 3 + 4(3) \\ \\ \tt \: = 3 + 6 + 3 + 12 \\ \\ \large \tt \: = 24\\ \\ \tt \pink{ LHS = RHS} \\ \\ \tt \purple{\therefore \: the \: \: value \: \: of \: \: y \: \: = 3} \\ \\ \large\tt \: Hence, \: \: checked!$