1. Solve by factorisation: 2y2+y-10=0 *
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Answers
Step-by-step explanation:
(2y+5)(y-2)
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Answer:
The answer is the picture
Step-by-step explanation:
The first term is, 2y2 its coefficient is 2 .
The middle term is, -y its coefficient is -1 .
The last term, "the constant", is -10
Step-1 : Multiply the coefficient of the first term by the constant 2 • -10 = -20
Step-2 : Find two factors of -20 whose sum equals the coefficient of the middle term, which is -1 .
-20 + 1 = -19
-10 + 2 = -8
-5 + 4 = -1 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -5 and 4
2y2 - 5y + 4y - 10
Step-4 : Add up the first 2 terms, pulling out like factors :
y • (2y-5)
Add up the last 2 terms, pulling out common factors :
2 • (2y-5)
Step-5 : Add up the four terms of step 4 :
(y+2) • (2y-5)
Which is the desired factorization
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